A) \[{{x}^{2}}+{{y}^{2}}<1\]
B) \[{{x}^{2}}-{{y}^{2}}<1\]
C) \[{{x}^{2}}+{{y}^{2}}>1\]
D) \[2{{x}^{2}}+3{{y}^{2}}<1\]
Correct Answer: C
Solution :
Let\[z=x+iy\] Given, \[\left| \frac{z+2i}{2z+i} \right|<1\] \[\Rightarrow \] \[\frac{\sqrt{{{(x)}^{2}}+{{(y+2)}^{2}}}}{\sqrt{{{(2x)}^{2}}+{{(2y+1)}^{2}}}}<1\] \[\Rightarrow \] \[{{x}^{2}}+{{y}^{2}}+4+4y<4{{x}^{2}}+4{{y}^{2}}+1+4y\] \[\Rightarrow \] \[3{{x}^{2}}+3{{y}^{2}}>3\] \[\Rightarrow \] \[{{x}^{2}}+{{y}^{2}}>1\]
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