question_answer

A battery of emf 10 V is connected to resistance as shown in figure. The potential difference \[{{V}_{A}}-{{V}_{B}}\]between the points A and B is

A)  -2V                                       

B)  2V

C)  5V                         

D)        \[\frac{20}{11}V\]

Correct Answer: B

Solution :

\[{{R}_{eq}}=5\Omega \], current\[i=\frac{10}{5}=2A\]and current in each branch = 1 A. Potential difference between\[C\]and\[A\],                 \[{{V}_{C}}-{{V}_{A}}=1\times 1=1\,\,V\]                              ? (i) Potential difference between\[C\]and\[B\]                 \[{{V}_{C}}-{{V}_{B}}=1\times 3=3\,\,V\]                              ... (ii) On solving Eqs. (i) and (ii) we get                 \[{{V}_{A}}-{{V}_{B}}=2V\]