Manipal Engineering Manipal Engineering Solved Paper-2010

  • question_answer
    The angle of minimum deviation \[{{\delta }_{m}}\] for an equilateral glass prism is 30°. Refractive index of the prism is

    A)  \[1/\sqrt{2}\]                                   

    B) \[\sqrt{2}\]

    C)  \[2\sqrt{2}\]                     

    D)         \[1/2\sqrt{2}\]

    Correct Answer: B

    Solution :

    \[A={{60}^{o}},\,\,{{\delta }_{m}}={{30}^{o}}\] As           \[\mu =\sin \frac{\left( \frac{1+{{\delta }_{m}}}{2} \right)}{\sin \left( \frac{A}{2} \right)}\] \[\therefore \]  \[\mu =\sin \frac{\frac{({{60}^{o}}+{{30}^{o}})}{2}}{\sin \left( \frac{{{60}^{o}}}{2} \right)}=\frac{\sin {{45}^{o}}}{\sin {{30}^{o}}}\]                 \[=\frac{1/\sqrt{2}}{1/2}=\frac{2}{\sqrt{2}}=\sqrt{2}\]


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