A) 540 cal
B) 40 cal
C) 500 cal
D) zero
Correct Answer: C
Solution :
According to first law of thermodynamics \[\Delta Q=\Delta U+\Delta W\] \[\therefore \] \[\Delta U=\Delta Q-\Delta W\] \[=540-\frac{p({{V}_{2}}-{{V}_{1}})}{J}\] \[=540-\frac{1.013\times {{10}^{5}}\times [(1671-1)\times {{10}^{-6}}]}{4.2}\] \[=540-40=500\,\,cal\]You need to login to perform this action.
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