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Manipal Engineering Manipal Engineering Solved Paper-2010

  • question_answer
    A constant torque acting on a uniform circular wheel   changes   its angular momentum from \[{{A}_{0}}\] to \[4{{A}_{0}}\] in 4s. The magnitude of this torque is

    A)  \[\frac{3{{A}_{0}}}{4}\]                                

    B) \[{{A}_{0}}\]

    C)  4\[{{A}_{0}}\]                  

    D)         12\[{{A}_{0}}\]

    Correct Answer: A

    Solution :

    Torque\[\overset{\to }{\mathop{\tau }}\,=\frac{\overset{\to }{\mathop{dL}}\,}{dt}=\frac{{{L}_{2}}-{{L}_{1}}}{\Delta t}=\frac{4{{A}_{0}}-{{A}_{0}}}{4}=\frac{3{{A}_{0}}}{4}\]


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