Manipal Engineering Manipal Engineering Solved Paper-2011

  • question_answer
    If 10% of the current passes through a moving coil galvanometer of resistance \[99\,\Omega \]. Then the shunt resistance will be

    A)  9.9\[\Omega \]                               

    B)  11\[\Omega \]

    C)  10 \[\Omega \]               

    D)         9 \[\Omega \]

    Correct Answer: B

    Solution :

    Resistance of galvanometer\[G=99\Omega \]. Resistance of shunt\[S=\frac{{{i}_{g}}G}{i-{{i}_{g}}}\]                                 \[=\frac{10\times 99}{100-10}=11\Omega \]


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