2. Solved Papers
  3. Manipal Engineering

Manipal Engineering Manipal Engineering Solved Paper-2011

  • question_answer
    In the following reaction, which choice has value twice that of the equivalent weight of the oxidizing agent?                 \[S{{O}_{2}}+2{{H}_{2}}O\xrightarrow{{}}S+2{{H}_{2}}{{O}_{2}}\]

    A)  16                                         

    B)  48

    C)  64                         

    D)         32

    Correct Answer: A

    Solution :

    \[S{{O}_{2}}+{{H}_{2}}O\xrightarrow{{}}3S+2{{H}_{2}}O\] Eq. wt. of\[S{{O}_{2}}\]in the reaction \[=\frac{molar\,\,mass\,\,of\,\,S{{O}_{2}}}{change\,\,in\,\,oxidation\,\,state}=\frac{64}{4}=16\]


You need to login to perform this action.
You will be redirected in 3 sec spinner