A) \[600\]
B) \[200\]
C) \[250/\pi \]
D) \[500\]
Correct Answer: C
Solution :
From the formula,\[\omega =\frac{1}{\sqrt{LC}}\] Given, \[L=8H\] \[C=0.5\,\,\mu F=0.5\times {{10}^{-6}}F\] Comparing the powers, we get \[\therefore \] \[\omega =\frac{1}{\sqrt{8\times 0.5\times {{10}^{-6}}}}\] \[\Rightarrow \] \[\omega =\frac{1}{2\times {{10}^{-3}}}=500\] \[\Rightarrow \] \[\omega =\frac{250}{\pi }rad/s\]
You need to login to perform this action.
You will be redirected in
3 sec
