Manipal Engineering Manipal Engineering Solved Paper-2012

  • question_answer
    A\[220\,\,V\]main supply is connected to a resistance of\[100k\Omega \]. The effective current is

    A) \[2.2\,\,mA\]                    

    B) \[2.2\sqrt{2}mA\]

    C) \[\frac{2.2}{\sqrt{2}}mA\]           

    D)         None of these

    Correct Answer: A

    Solution :

    Effective current is the rms value. Here,\[220\,\,V\]is the labelled value of\[AC\]which is also the rms value. Hence,                 \[{{I}_{rms}}=\frac{{{E}_{rms}}}{R}\]                 \[{{I}_{rms}}=\frac{220}{100\times {{10}^{3}}}\]                 \[{{I}_{rms}}=2.2\,\,mA\]


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