A) \[_{\bullet }^{\bullet }CHBr\]
B) \[_{\bullet }^{\bullet }CHCl\]
C) \[_{\bullet }^{\bullet }CPhBr\]
D) \[_{\bullet }^{\bullet }CPhCl\]
Correct Answer: B
Solution :
\[PhCHClBr\xrightarrow[-t-BuOH]{tBu{{O}^{-}}}Ph{{C}^{-}}ClBr\xrightarrow{{}}Ph\overset{\centerdot \,\,\,\centerdot }{\mathop{C}}\,Cl\]
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