Manipal Engineering Manipal Engineering Solved Paper-2012

  • question_answer
    In an election, number of candidates exceeds the number to be elected by 2. A man can vote in 56 ways. Then, the number of candidates is

    A)  5                                            

    B)  6

    C)  7                            

    D)         8

    Correct Answer: B

    Solution :

    Let number of candidates be n. Therefore,\[n-2\] are to be elected and so one can vote up to\[(n-2)\]. Hence, .number of ways in which one can vote                 \[{{=}^{n}}{{C}_{1}}{{+}^{n}}{{C}_{2}}+...{{+}^{n}}{{C}_{n-2}}=56\](given) \[\Rightarrow \]               \[{{2}^{n}}-{{(}^{n}}{{C}_{0}}{{+}^{n}}{{C}_{n-1}}{{+}^{n}}{{C}_{n}})=56\] \[\Rightarrow \]               \[{{2}^{n}}-n=58\,\,\,\Rightarrow \,\,\,{{2}^{n}}=58+n\] Which is satisfied by\[n=6\]only.


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