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Manipal Engineering Manipal Engineering Solved Paper-2012

  • question_answer
    A five digit number divisible by 3 is to be formed using the digits 0, 1, 2, 3, 4 and 5, without repetition. The total number of ways this can be done, is

    A)  216                                       

    B)  240

    C)  600                       

    D)         3125

    Correct Answer: A

    Solution :

    Since, a five digit number is formed by using digits 0,1, 2, 3, 4 and 5, divisible by 3 i.e., only possible when sum of digits is multiple of three which gives two cases. Case I Using digits 0, 1, 2, 4, 5 the number of ways\[=4\times 4\times 3\times 2\times 1=96\]. Case II Using digits 1, 2, 3, 4, 5 the number of ways\[=5\times 4\times 3\times 2\times 1=120\] \[\therefore \]Total numbers formed\[=120+96=216\]


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