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Manipal Engineering Manipal Engineering Solved Paper-2013

  • question_answer
    When a force\[{{F}_{1}}\]acts on a particle, frequency is \[6Hz\]and when a force\[{{F}_{2}}\]acts, frequency is\[8Hz\]. What is the frequency when both the forces act simultaneously in same direction?

    A) \[12Hz\]                              

    B) \[25Hz\]

    C) \[10Hz\]                              

    D) \[5Hz\]

    Correct Answer: C

    Solution :

    \[F=mr\,\,{{\omega }^{2}}=mr\times {{(2\pi mm)}^{2}}=4{{\pi }^{2}}m{{m}^{2}}\] \[F\propto 2{{n}^{2}}\] \[F={{F}_{1}}+{{F}_{2}}\] \[{{n}^{2}}=n_{1}^{2}+n_{2}^{2}\] \[n=\sqrt{n_{1}^{2}+n_{2}^{2}}\] \[n=\sqrt{{{(6)}^{2}}+{{(8)}^{2}}}\] \[n=\sqrt{100}=10\,\,Hz\]


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