A) \[N\]
B) \[O\]
C) \[{{O}^{+}}\]
D) \[Na\]
Correct Answer: C
Solution :
\[N(7)\]and\[{{O}^{+}}(8-1=7)=1{{s}^{2}}2{{s}^{2}}\underbrace{2p_{x}^{1}2p_{y}^{1}2p_{z}^{1}}_{Maximum\,\,multiplicity\,\,most\,\,stable}\] \[O=1{{s}^{2}},\,\,2{{s}^{2}}2p_{x}^{2},\,\,2p_{y}^{1},\,\,2p_{z}^{1}\] Ionisation potential is dependent on the value of\[Z\]. \[Z\]of\[{{O}^{+}}(8)>Z\]of\[N(7)\] Thus, ionisation potential of\[{{O}^{+}}>N\] Na with one valence electron has least ionisation potential.
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