A) \[Zn+Ni\xrightarrow{{}}Z{{n}^{2+}}+N{{i}^{2+}}\]
B) \[Zn+N{{i}^{2+}}\xrightarrow{{}}Z{{n}^{2+}}+Ni\]
C) \[Ni+Z{{n}^{2+}}\xrightarrow{{}}N{{i}^{2+}}+Zn\]
D) \[N{{i}^{2+}}+2K\xrightarrow{{}}2{{K}^{+}}+Ni\]
Correct Answer: B
Solution :
\[Zn\]is at lower potential, it will be oxidised and the cell reaction will be . \[Zn(s)+N{{i}^{2+}}(aq)\xrightarrow{{}}Z{{n}^{2+}}(aq)+Ni(s)\]
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