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Manipal Engineering Manipal Engineering Solved Paper-2013

  • question_answer
    Find the greatest value of xyz for positive values of\[x,\,\,y,\,\,z\]subject to the condition\[xy+yz+zx=12\].

    A)  64                         

    B)  8       

    C)  16         

    D)         32

    Correct Answer: B

    Solution :

    By hit and trial method taking\[x=y=z=2\], we get\[xy+yz+zx=12\] and        \[xyz=8\].


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