Manipal Medical Manipal Medical Solved Paper-2000

  • question_answer
    A man of weight 75 kg is standing m an elevator which is moving with an acceleration of\[5\text{ }m/{{s}^{2}}\]in upward direction the apparent weight of the man will be:\[(g=10m/{{s}^{2}})\]

    A)  1425 N          

    B)  1375 N

    C)  1250 N          

    D)  1125 N

    Correct Answer: D

    Solution :

     Here: Mass of the man m =75 kg Acceleration of elevator \[a=5\text{ }m/{{s}^{2}}\] The apparent weight of the man is \[W=m(g+a)=75\times (10+5)\] \[=1125N\]


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