A) 1.5 V
B) 2.6 V
C) 4.8 V
D) 9.8 V
Correct Answer: C
Solution :
Current across the \[3\,\Omega \]resistor\[=0.8\text{ }A\] The current through the parallel resistance of\[6\,\Omega \]. is \[=\frac{0.8\times 3}{6}=0.4A\] Hence, the total current across Q is \[=0.8+0.4=1.2\] Now, potential across\[4\,\Omega \]resistor is \[=4\times 1.2=4.8\]
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