A) \[8\alpha ,8\beta \]
B) \[8\alpha ,6\beta \]
C) \[6\alpha ,6\beta \]
D) \[6\alpha ,8\beta \]
Correct Answer: B
Solution :
As it is clear that the emission of\[\alpha \]and\[\beta -\]particles can be shown by the relation, \[_{Z}{{X}^{A}}{{\xrightarrow[{}]{-\alpha }}_{Z-2}}{{X}^{A-4}}\] and \[_{Z}{{X}^{A}}{{\xrightarrow[{}]{-\beta }}_{Z+1}}{{X}^{A}}\] Hence, for a radioactive decay\[8\alpha \]and \[6\beta -\] particles would be emitted.
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