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Manipal Medical Manipal Medical Solved Paper-2000

  • question_answer
    The emf of a galvanic cell, with electrode potential of zinc\[=+0.76V\]and that of copper = 0.34 V, is:

    A)  \[0.76V\]            

    B)  \[1.1V\]

    C)  \[-1,1V\]

    D)  \[1.6V\]

    Correct Answer: B

    Solution :

     The emf of a galvanic cell = electrote potential    electrode potential         \[of\text{ }zinc\,\,\,\,\,\,~~~~~~~-~\,\,\,\,\,\,\,\,\,\,\,~~of\text{ }copper\] \[=0.76-(-0.34)=1.1\text{ }V\]


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