A) 8.74
B) 18.76
C) 24.06
D) 26.06
Correct Answer: D
Solution :
The entropy change \[=\frac{heat\text{ }of\text{ }vaporisation}{temperature}\] Here, heat of vaporisation = 540 cal/gm \[=540\times 18\text{ }cal\text{ }mo{{l}^{-1}}\] Temperature of water\[=100+273=373\text{ }K\] \[\therefore \]entropy change\[=\frac{540\times 18}{373}\] \[=26.06\text{ }cal\text{ }mo{{l}^{-1}}{{K}^{-1}}\]You need to login to perform this action.
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