A) \[sp\]
B) \[s{{p}^{2}}\]
C) \[s{{p}^{3}}\]
D) \[s{{p}^{3}}d\]
Correct Answer: B
Solution :
In the formation of\[B{{F}_{3}}\]molecule, one\[s\]and 2p orbitals hybridise. Therefore, it is\[s{{p}^{2}}\].
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