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Manipal Medical Manipal Medical Solved Paper-2000

  • question_answer
    An organic compound on analysis produce   \[C=40%,\] \[H=13.33\] and \[N=46.67%.\] The empirical formula of this compound is

    A)  \[C{{H}_{5}}N\]

    B)  \[C{{H}_{4}}N\]

    C)  \[{{C}_{2}}{{H}_{5}}N\]

    D)  \[{{C}_{2}}{{H}_{4}}N\]

    Correct Answer: B

    Solution :

     
    Element Percentages Relative no. of mol. Simple ratio of mol. Simplest whole number ratio
    C 40 \[\frac{40}{12}=3.33\] \[\frac{3.33}{3.33}=1\] 1
    H 13.33 \[\frac{13.33}{1}\] =13.33 \[\frac{13.33}{3.33}=4\] 4
    N 46.67 \[\frac{46.67}{14}=3.33\] \[\frac{3.33}{3.33}=1\] 1
    Hence, the empirical formula\[=C{{H}_{4}}N\]


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