A) \[3.125\times {{10}^{16}}\]
B) \[3.125\times {{10}^{8}}\]
C) \[3.125\times {{10}^{30}}\]
D) \[3.125\times {{10}^{25}}\]
Correct Answer: A
Solution :
Here: Energy per disintegration \[=200\text{ }MeV\] Power obtained in the reactor \[P=1000kW={{10}^{6}}W\] Energy received from reactor is given by, \[{{10}^{6}}J/s=\frac{{{10}^{6}}}{1.6\times {{10}^{-19}}}\] \[=6.25\times {{10}^{18}}eV/s\] \[=6.25\text{ }MeV/s\times {{10}^{18}}\] Number of disintegration \[=\frac{power\text{ }of\text{ }the\text{ }reactor}{energy\text{ }per\text{ }disintegration}\] \[=\frac{6.25\times {{10}^{18}}}{200}=3.125\times {{10}^{16}}\]
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