Manipal Medical Manipal Medical Solved Paper-2001

  • question_answer
    The angular momentum of a body with mass \[m,\]moment of inertia and angular velocity\[\omega \] rad/sec will be equal to:

    A)  \[I/{{\omega }^{2}}\]               

    B)  \[I/\omega \]

    C)  \[I\omega \]

    D)  \[I{{\omega }^{2}}\]

    Correct Answer: C

    Solution :

     Moment of inertia of body\[=I\] Angular velocity of body\[=\omega \]rad/sec Then angular momentum of the body is \[I={{m}_{1}}{{\upsilon }_{1}}{{R}_{1}}+{{m}_{2}}{{\upsilon }_{2}}{{R}_{2}}+...\] \[={{m}_{1}}(\omega {{R}_{1}}){{R}_{1}}+{{m}_{2}}(\omega {{R}_{2}}){{R}_{2}}+....\] \[={{m}_{1}}R_{1}^{2}\omega +{{m}_{2}}R_{2}^{2}\omega +.....\] or        \[(\Sigma m{{R}^{2}})\omega =I\omega \] (where\[I\]is\[m{{r}^{2}}\])


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