A) it occupies 2.24 litres at NTP
B) it corresponds to\[\frac{1}{2}\]mole of CO
C) it corresponds to same mole of CO and nitrogen gas
D) it corresponds to\[3.01\times {{10}^{23}}\] molecules of CO
Correct Answer: A
Solution :
We know that 14 gm\[CO=\frac{14}{28}=\]0.5 mol Therefore, it corresponds to\[\frac{1}{2}\]mole of CO and nitrogen gas. 0.5 mol is equivalent to \[3.01\times {{10}^{23}}\]molecules.
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