A) \[7.11\times {{10}^{-3}}\]minute
B) \[14.22\times {{10}^{-3}}\]minute
C) \[7.11\times {{10}^{-6}}\]minute
D) \[14.22\times {{10}^{-6}}\]minute
Correct Answer: A
Solution :
In 40.5 minute 25% reactant decomposed, the reactant remained is 75%. \[\therefore \] \[(a-x)=0.75\,a\] We know, that\[{{K}_{t}}=\frac{2.303}{t}\log \frac{a}{a-x}\] \[=\frac{2.303}{40.5}\log \frac{a}{0.75a}\] \[=7.11\times {{10}^{-3}}\]minutes
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