A) \[1.50\times {{10}^{24}}\]
B) \[2.04\times {{10}^{24}}\]
C) \[3.01\times {{10}^{24}}\]
D) \[4.09\times {{10}^{24}}\]
Correct Answer: C
Solution :
One mole of\[CaC{{O}_{3}}\]contains protons = atomic number of\[Ca+\]atomic number of \[C+\]atomic number of \[3[O]\] \[=20+6+24=50\text{ }moles\] Number of protons in 10 gms of \[CaC{{O}_{3}}=\frac{10}{100}\times 50\times 6.02\times {{10}^{23}}\] \[=3.01\times {{10}^{24}}\]
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