Manipal Medical Manipal Medical Solved Paper-2002

  • question_answer
    The mass of ship is\[2\times {{10}^{7}}kg\]. On applying a fore of\[25\times {{10}^{5}}N,\]it is displaced through 25 m. After the displacement. The speed aquired by the ship will be:

    A)  12.5 m/s         

    B)  5m/s

    C)  3.7 m/s          

    D)  2.5 m/s

    Correct Answer: D

    Solution :

     Here : Mass of ship \[m=2\times {{10}^{7}}kg,\] Force \[F=25\times {{10}^{5}}N\] Displacement \[s=25\text{ }m\] According the Newtons second law of motion \[F=na\] or      \[a=\frac{F}{m}=\frac{25\times {{10}^{5}}}{2\times {{10}^{7}}}\] \[=12.5\times {{10}^{-2}}m/{{s}^{2}}\] The relation for find! velocity is \[{{\upsilon }^{2}}={{u}^{2}}+2as\] or         \[{{\upsilon }^{2}}=0+2\times (12.5\times {{10}^{-2}})\times 25\] or           \[\upsilon =\sqrt{6.25}=2.5m/s\]


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