Manipal Medical Manipal Medical Solved Paper-2002

  • question_answer
    A radioactive element has half life of 3.6 days. In what time will it be left 1/32nd undecayed?

    A)  4 days           

    B)  12 days

    C)  18 days          

    D)  24 days

    Correct Answer: C

    Solution :

     Here: Half life\[{{T}_{1/2}}=\]3.6 days Amount left after time\[t,\] \[N=\frac{1}{32}\times {{N}_{0}}\] Number of half lives in time,\[(n)\]is given by \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{n}}\] Or \[\frac{\frac{{{N}_{0}}}{32}}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{n}}\] Or \[\frac{1}{32}=\frac{1}{{{2}^{n}}}\] Or \[n=5\]or\[\frac{1}{{{t}_{1/2}}}=5\] Hence, time of deeay \[t=5\times \frac{{{t}_{1}}}{2}=5\times 3.5\approx 18\,days\]


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