A) \[990\,cm/{{s}^{2}}\]
B) \[860\,cm/{{s}^{2}}\]
C) \[720\,cm/{{s}^{2}}\]
D) \[493\,cm/{{s}^{2}}\]
Correct Answer: D
Solution :
Here: Length of the string \[l=50\text{ }cm\] Time period \[T=\frac{20}{10}=2\text{ }sec\] The angular velocity \[\omega =\frac{2\pi }{T}=\frac{2\pi }{2}=3.14\] Hence, magnitude of acceleration is given by \[a={{\omega }^{2}}\times l={{(3.14)}^{2}}\times 50=493\text{ }cm/se{{c}^{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec
