A) catalyst
B) oxidising agent
C) reducing agent
D) acid as well as oxidant
Correct Answer: D
Solution :
\[2Ag+2{{H}_{2}}S{{O}_{4}}\xrightarrow[{}]{{}}A{{g}_{2}}S{{O}_{4}}\] \[+2{{H}_{2}}O+S{{O}_{2}}\] Here\[{{H}_{2}}S{{O}_{4}}\]acts as an acid because its oxidation number is + 6 in\[A{{g}_{2}}S{{O}_{4}}\]. It also acts as an oxidant because\[{{H}_{2}}S{{O}_{4}}\]gives\[S{{O}_{2}}\] \[\overset{+6}{\mathop{{{H}_{2}}S{{O}_{4}}}}\,\xrightarrow[{}]{{}}\overset{+4}{\mathop{S{{O}_{2}}}}\,\]
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