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Manipal Medical Manipal Medical Solved Paper-2003

  • question_answer
    \[E{}^\circ\] for \[F{{e}^{2+}}+2{{e}^{-}}\xrightarrow[{}]{{}}Fe\] is \[-0.44\] volt and \[E{}^\circ \] for \[Z{{n}^{2+}}+2{{e}^{-}}\xrightarrow[{}]{{}}Zn\] is \[-0.76\]volt thus:

    A) \[Zn\] is more electropositive than\[Fe\]

    B)  \[Zn\] is more electronegative than \[Fe\]

    C) \[Fe\]is more electropositive than \[Zn\]

    D)  none.

    Correct Answer: A

    Solution :

     High value for \[E_{red}^{{}^\circ }\].shows more electro negativity i.e.,\[Zn\]is. more electropositive than \[Fe\]. \[(E_{Z{{n}^{2+}}/Zn}^{o}<E_{F{{e}^{2+}}/Fe}^{o})\]


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