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Manipal Medical Manipal Medical Solved Paper-2003

  • question_answer
    20g of a binary electrolyte (mol. Wt = 100) are dissolved in 500 g of water. The depression in freezing point of the solution is\[0.74{}^\circ C\](\[{{K}_{f}}=\]\[1.86\text{ }K\text{ }molalit{{y}^{-1}}\]) The degree of ionization of the electrolyte is:

    A)  0 %          

    B)  100 %

    C)  75%          

    D)  50 %

    Correct Answer: A

    Solution :

     \[\Delta T=\frac{1000\times {{K}_{f}}\times \omega }{m\times 500}\] \[0.74=\frac{1000\times 1.86\times 20}{m\times 500}\] \[m=100\] Actual molecular mass =100 \[\therefore \]The degree of ionization of the electrolyte is 0%.


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