A) has two hydroxyl groups in its structure
B) is a derivative of sulphur dioxide
C) is a dibasic acid
D) has greater affinity for water
Correct Answer: A
Solution :
\[PC{{l}_{5}}+HO-\underset{\begin{smallmatrix} |\,\,| \\ O \end{smallmatrix}}{\overset{\begin{smallmatrix} O \\ |\,\,\,| \end{smallmatrix}}{\mathop{S}}}\,-OH\xrightarrow[{}]{{}}\] \[Cl-\underset{\begin{smallmatrix} |\,\,| \\ O \end{smallmatrix}}{\overset{\begin{smallmatrix} O \\ |\,\,\,| \end{smallmatrix}}{\mathop{S}}}\,-Cl+POC{{l}_{3}}+{{H}_{2}}O\] \[PC{{l}_{5}}\]attacks\[-OH\]group and replace it by\[-Cl\] group. Hence, reaction of\[PC{{l}_{5}}\]with\[{{H}_{2}}S{{O}_{4}}\]shows the presence of 2\[-OH\] groups in\[{{H}_{2}}S{{O}_{4}}\].
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