A) zero
B) 2.0 m/s
C) 0.3 m/s
D) 0.4 m/s
Correct Answer: A
Solution :
Given: \[A=10\text{ }cm=0.1\text{ }m,\text{ }T=4\text{ }sec,\] \[t=1\text{ }sec\] Speed of oscillating simple pendulum is given by \[y=A\sin \omega t\] \[\frac{dy}{dt}=\upsilon =A\omega \cos (\omega t)\] \[=A\times \frac{2\pi }{T}\cos \left( \frac{2\pi }{T}t \right)\] \[=\frac{2\pi \times 0.1}{4}\cos \left( \frac{2\pi \times 1}{4} \right)\] \[=\frac{2\pi \times 0.1}{4}\cos \frac{\pi }{2}=0\]
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