A) moving up with uniform velocity
B) moving up with uniform acceleration
C) moving down with uniform acceleration
D) moving around the earth in geostationary orbit
Correct Answer: A
Solution :
The time period of simple pendulum is \[T=2\pi \sqrt{\frac{l}{g}}\] \[\Rightarrow \] \[T\propto \frac{1}{\sqrt{g}}\] Since, time period of second pendulum decreases, so, it implies that effective value of g is increasing. Thus, it means that rocket is accelerating upwards.
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