Manipal Medical Manipal Medical Solved Paper-2004

  • question_answer
    In Youngs double-slit experiment, distance between slits is 0.28 mm, distance between slits and screen is 1.4 m and distance between central bright fringe and third bright fringe is 0.9 cm. What is the wavelength of light used?

    A)  \[5000\overset{o}{\mathop{\text{A}}}\,\]      

    B)  \[6000\overset{o}{\mathop{\text{A}}}\,\]

    C)  \[7000\overset{o}{\mathop{\text{A}}}\,\]   

    D)  \[9000\overset{o}{\mathop{\text{A}}}\,\]

    Correct Answer: B

    Solution :

     Given: \[D=1.4\text{ }m,\text{ }n=3,\] \[d=0.28\text{ }mm=0.28\times {{10}^{-3}}m,\] \[{{x}_{3}}=0.9\text{ }cm=0.9\times {{10}^{-2}}m\] From the relation \[{{x}_{3}}=\frac{nD\lambda }{d}\] \[\therefore \] \[\lambda =\frac{{{x}_{3}}\times d}{nD}=\frac{0.9\times {{10}^{-2}}\times 0.28\times {{10}^{-3}}}{3\times 1.4}\] \[=6\times {{10}^{-7}}m\] \[=6000\times {{10}^{-10}}m\] \[=6000\overset{o}{\mathop{\text{A}}}\,\]


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