Manipal Medical Manipal Medical Solved Paper-2004

  • question_answer
    In the nth orbit of hydrogen atom, ratio of its radius and de-Broglie wavelength associated with it, is:

    A)  \[\frac{1}{2\pi n}\]

    B)  \[\frac{1}{2\pi {{n}^{2}}}\]

    C)  \[\frac{n}{2\pi }\]

    D)  \[\frac{{{n}^{2}}}{2\pi }\]

    Correct Answer: C

    Solution :

     The velocity of electron in nth orbit is given by \[\upsilon =\frac{nh}{2\pi m{{r}_{n}}}\] ?.(1) Also,      \[\lambda =\frac{h}{p}=\frac{h}{m\upsilon }\]               ...(2) From eqs. (1) and (2), we have \[\lambda =\frac{h}{m\frac{nh}{2\pi m{{r}_{n}}}}\] \[=\frac{2\pi {{r}_{n}}}{n}\] \[\therefore \] \[\frac{{{r}_{n}}}{\lambda }=\frac{n}{2\pi }\]


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