A) \[4.3\times {{10}^{-2}}N{{m}^{-1}}\]
B) \[5.6\times {{10}^{-2}}N{{m}^{-1}}\]
C) \[6.3\times {{10}^{-2}}N{{m}^{-1}}\]
D) \[7.3\times {{10}^{-2}}N{{m}^{-1}}\]
Correct Answer: C
Solution :
Given that Density of liquid \[(D)=800\text{ }kg{{m}^{-3}}\] Height of liquid \[(h)=4\text{ }cm=0.04\text{ }m\] Acceleration due to gravity \[(g)=9.8m/{{s}^{2}}\] Diameter of tube \[(d)=0.8\text{ }mm\] Radius of tube \[(r)=0.4\text{ }mm=4\times {{10}^{-4}}m\] Surface tension \[(T)=?\] By using \[T=\frac{rhDg}{2}\] \[=\frac{(4\times {{10}^{-4}})\times (.04)\times 800\times 9.8}{2}\] \[=4\times 4\times 4\times 98\times {{10}^{-5}}\] Hence, \[T=6.272\times {{10}^{-2}}=6.3\times {{10}^{-2}}N{{m}^{-1}}\]
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