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Manipal Medical Manipal Medical Solved Paper-2005

  • question_answer
    At\[90{}^\circ C,\]pure water has\[{{H}_{3}}{{O}^{+}}\]ion concentration of \[{{10}^{-6}}mol/{{L}^{-1}}\]. The\[{{K}_{\omega }}\]at \[90{}^\circ C\]is:

    A)  \[{{10}^{-6}}\]

    B)  \[{{10}^{-14}}\]

    C)  \[{{10}^{-12}}\]

    D)  \[{{10}^{-8}}\]

    Correct Answer: C

    Solution :

     \[{{K}_{\omega }}=[{{H}^{+}}][O{{H}^{-}}]\] \[=({{10}^{-6}})\times ({{10}^{-6}})\]\[(\because \Delta {{n}_{g}}=-ve)\] \[={{10}^{-12}}\]


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