2. Solved Papers
  3. Manipal Medical

Manipal Medical Manipal Medical Solved Paper-2006

  • question_answer
    A monoatomic gas supplied the heat Q very slowly keeping the pressure constant. The work done by the gas will be:

    A)  \[\frac{2}{3}Q\]

    B)  \[\frac{3}{5}Q\]

    C)  \[\frac{2}{5}Q\]

    D)  \[\frac{1}{5}Q\]

    Correct Answer: C

    Solution :

     For monoatomic gas at constant pressure \[\frac{\Delta U}{Q}=\frac{3}{5}\] Or \[\Delta U=\frac{3Q}{5}\] Now, applying first law of thermodynamics \[W=\Delta Q-\Delta U\] \[=Q-\frac{3Q}{5}\] \[=\frac{2Q}{5}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner