A) 0.6 J
B) 0.06 J
C) 0.03 J
D) 0.3 J
Correct Answer: C
Solution :
The energy stored in the capacitor is given by \[U=\frac{1}{2}C{{V}^{2}}\] Given, \[C=6\times {{10}^{-6}}F,\text{ }V=100\text{ }V\] So, \[U=\frac{1}{2}\times 6\times {{10}^{-6}}\times {{(100)}^{2}}\] \[=3\times {{10}^{-2}}J=0.03\text{ }J\]
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