A) \[2E\]
B) \[E\]
C) zero
D) none of these
Correct Answer: C
Solution :
If\[I\]be the current in the circuit, then \[E+E=Ir+Ir=2Ir\] or \[I=\frac{E}{r}\] \[\therefore \] \[{{V}_{x}}-{{V}_{y}}=E-Ir\] \[=E-\frac{E}{r}\times r=0\]
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