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Manipal Medical Manipal Medical Solved Paper-2006

  • question_answer
    The amount of urea to be dissolved in 500 cc of water\[(K=1.86{}^\circ C)\]to produce a depression of \[0.186{}^\circ C\]in the freezing point is:

    A)  \[9g\]             

    B)  \[6g\]

    C)  \[3g\]             

    D)  \[0.3g\]

    Correct Answer: C

    Solution :

     We know that, w (mass of solute) \[=\frac{m\times \Delta {{T}_{f}}\times W}{1000\times {{K}_{f}}}\] \[m=\]mol. wt. of urea (60) \[\Delta {{T}_{f}}=0.186{}^\circ C\] \[{{K}_{f}}=1.86{}^\circ ,W=500\,g\] \[=\frac{60\times 0.186\times 500}{1000\times 1.86}\] \[=3g\]


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