Manipal Medical Manipal Medical Solved Paper-2006

  • question_answer
    Oxidation number of\[N\]in\[N{{H}_{3}}\](hydrazoic acid) is:

    A)  \[-\frac{1}{3}\]

    B)  \[+3\]

    C)  \[0\]

    D)  \[-3\]

    Correct Answer: A

    Solution :

     \[{{N}_{3}}H\](hydrozoic acid) \[+3(x)+1=0\] \[3x+1=0\] \[x=-\frac{1}{3}\]


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