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Manipal Medical Manipal Medical Solved Paper-2007

  • question_answer
    A coil of 40 H inductance is connected in series with a resistance of \[8\,\Omega \]and the combination is joined to the terminals of a 2 V battery. The time constant of the circuit is

    A)  5 s           

    B)  \[\frac{1}{5}s\]

    C)  40 s          

    D)  20 s

    Correct Answer: A

    Solution :

     Time constant of L-R circuit is, \[\tau =\frac{L}{R}\] Here, \[L=40H,R=8\,\Omega ,E=2V\] \[\therefore \] \[\tau =\frac{40}{8}=5s\] NOTE: At a time equal to one time constant the current has risen to\[\left( 1-\frac{1}{e} \right)\]or about 63% of its initial value\[{{i}_{0}}\].


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