A) 5kV
B) 50 kV
C) 5V
D) 50V
Correct Answer: B
Solution :
Key Idea: When bullet of mass m and charge q is accelerated through potential difference of V volt, then it attains a kinetic energy equal to\[qV\]. Kinetic energy of bullet \[=qV\] ie, \[\frac{1}{2}m{{v}^{2}}=qV\] \[\Rightarrow \] \[V=\frac{m{{v}^{2}}}{2q}\] Given, \[m=2g=2\times {{10}^{-3}}kg,v=10m/s,\] \[q=2\mu C=2\times {{10}^{-6}}C\] Substituting the values in relation for V, we obtain \[V=\frac{2\times {{10}^{-3}}\times {{(10)}^{2}}}{2\times 2\times {{10}^{-6}}}\] \[=50\times {{10}^{3}}V=50kV\]
You need to login to perform this action.
You will be redirected in
3 sec
