Manipal Medical Manipal Medical Solved Paper-2007

  • question_answer
    A hole is in the bottom of the tank having water. If total pressure at the bottom is 3 aim (1 atm \[={{10}^{5}}N-{{m}^{-2}}\]), then velocity of water flowing from hole is

    A)  \[\sqrt{400}\,m{{s}^{-1}}\]      

    B)  \[\sqrt{600}\,m{{s}^{-1}}\]

    C)  \[\sqrt{60}\,m{{s}^{-1}}\]       

    D)  none of these

    Correct Answer: A

    Solution :

    Let height of water column in the tank be h. Total pressure\[(P)=\]atmospheric pressure \[({{P}_{0}})+\]pressure due to water column in tank\[(P)\] \[\therefore \] \[p=p-{{p}_{0}}=3-1=2\,atm\] or      \[h\rho g=2\times {{10}^{5}}\] or \[h\times {{10}^{3}}\times 10=2\times {{10}^{5}}\] or          \[h=20m\] Hence, velocity of water coming from hole ie, velocity of efflux, is \[v=\sqrt{2gh}=\sqrt{2\times 10\times 20}\] \[=\sqrt{400}m{{s}^{-1}}\]


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