A) as elastic potential energy completely
B) as thermal energy completely
C) half as elastic potential energy and half as thermal energy
D) as kinetic energy of the load completely
Correct Answer: C
Solution :
When a metal wire elongates by hanging a load \[Mg\]on it, decrease in potential energy of the load \[=Mgl\] (where\[l=\]elongation in metal wire) Elastic potential energy stored in stretched wire \[=\frac{1}{2}\times Mgl\] Difference of\[Mgl\]and\[\frac{1}{2}Mgl\]appears as heat energy in the stretched wire. \[\therefore \] Energy appearing as heat\[=Mgl-\frac{1}{2}Mgl\] \[=\frac{1}{2}Mgl\]
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